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3.77x^2=4x+4
We move all terms to the left:
3.77x^2-(4x+4)=0
We get rid of parentheses
3.77x^2-4x-4=0
a = 3.77; b = -4; c = -4;
Δ = b2-4ac
Δ = -42-4·3.77·(-4)
Δ = 76.32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-\sqrt{76.32}}{2*3.77}=\frac{4-\sqrt{76.32}}{7.54} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+\sqrt{76.32}}{2*3.77}=\frac{4+\sqrt{76.32}}{7.54} $
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